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School1234789
@School1234789
March 2022
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xxxeol
РЕШЕНИЕ
1) BM = AM*sin30 = 26*0.5 = 13 - ОТВЕТ.
2) BM = AM*cos30 = 30*0.5=15 - ОТВЕТ
3) BM = AB*tg45 = 10*1 = 10 - ОТВЕТ
4) MH= BM*cos30 = 1/2*BM* √3
5)∠BAM = 30 и MH = 1/2* AM = 4 - ОТВЕТ
6) ∠MAB = ∠MBA=45
MH = 1/2*AB = 7.5 - ОТВЕТ
7) MH = 1/2*(2*R) = 6 - ОТВЕТ
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Answers & Comments
1) BM = AM*sin30 = 26*0.5 = 13 - ОТВЕТ.
2) BM = AM*cos30 = 30*0.5=15 - ОТВЕТ
3) BM = AB*tg45 = 10*1 = 10 - ОТВЕТ
4) MH= BM*cos30 = 1/2*BM* √3
5)∠BAM = 30 и MH = 1/2* AM = 4 - ОТВЕТ
6) ∠MAB = ∠MBA=45
MH = 1/2*AB = 7.5 - ОТВЕТ
7) MH = 1/2*(2*R) = 6 - ОТВЕТ