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kirillpolev123
@kirillpolev123
August 2022
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Verified answer
1)
sin(a)/sin(b)=n
sin(a)=sin(b)*n=sin(pi/6)*1,333=0,6665
a=arcsin(0,6665)~ 42 град
2)
1/sin(b)=n
sin(b)=1/n=1/1,6=0,625
b=arcsin(0,625)~38,7 град
3)
sin(a)/sin(b)=n
sin(a)=sin(b)*n=sin(a-c)*n=(sin(a)*cos(c)-sin(c)*cos(a))*n
sin(a)*(1-cos(c)*n)=-sin(c)*cos(a)*n
tg(a)=-sin(c)*n/(1-cos(c)*n)=-sin(pi/18)*1,333/(1-cos(pi/18)*1,333)=0,740124564
а=atan(0,740124564) ~36,5 град
4)
геометрическая задача (не физическая)
надо просто начертить аккуратно и получить ....
ответ 50 градусов
2 votes
Thanks 1
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Answers & Comments
Verified answer
1)sin(a)/sin(b)=n
sin(a)=sin(b)*n=sin(pi/6)*1,333=0,6665
a=arcsin(0,6665)~ 42 град
2)
1/sin(b)=n
sin(b)=1/n=1/1,6=0,625
b=arcsin(0,625)~38,7 град
3)
sin(a)/sin(b)=n
sin(a)=sin(b)*n=sin(a-c)*n=(sin(a)*cos(c)-sin(c)*cos(a))*n
sin(a)*(1-cos(c)*n)=-sin(c)*cos(a)*n
tg(a)=-sin(c)*n/(1-cos(c)*n)=-sin(pi/18)*1,333/(1-cos(pi/18)*1,333)=0,740124564
а=atan(0,740124564) ~36,5 град
4)
геометрическая задача (не физическая)
надо просто начертить аккуратно и получить ....
ответ 50 градусов