Заданы функции f(x)=3\2+x и g(x)=x+1\2 Найдите:
1) f(1)+g(3) 3) f(4)+g(4)
2) g(7)-f(7) 4) g(5)-f(10)
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Заданы функции f(x)=3\2+x и g(x)=x+1\2 Найдите:
1) f(1)+g(3) 3) f(4)+g(4)
2) g(7)-f(7) 4) g(5)-f(10)
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Verified answer
1)
f(1)=3/2+1=2,5
g(3)=3+1/2=3,5
f(1)+g(3)=2,5+3,5=6
2)
g(7)=7+1/2=7,5
f(7)=3/2+7=8,5
g(7)-f(7)=7,5-8,5=-1
3)
f(4)=3/2+4=5,5
g(4)=4+1/2=4,5
f(4)+g(4)=5,5+4,5=10
4)
g(5)=5+1/2=5,5
f(10)=3/2+10= 11,5
g(5)-f(10)=5,5-11,5=-6