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mklslajh
@mklslajh
July 2022
1
6
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Записаны первые три члена арифметической прогрессии: 6; 10; 14. Какое число стоит в этой арифметической прогрессии на 82-м месте?
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kopatel228
Verified answer
A1 = 6
a2 = 10
a3 = 14
d = a2 - a1 = 4
a82 = a1 + (n-1)d = 6 + 81d = 6 + 81 * 4 = 330
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Answers & Comments
Verified answer
A1 = 6a2 = 10
a3 = 14
d = a2 - a1 = 4
a82 = a1 + (n-1)d = 6 + 81d = 6 + 81 * 4 = 330