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vikasavchenko2
@vikasavchenko2
July 2022
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Записать квадратное уравнение
(у-5)(у-6)=2
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dudoser99
Y^2-5y-6y+30-2=0
y^2-11y+28=0
D=11^2-4*28=121-112=9
y1=(11+3)/2=7
y2=(11-3)/2=4
Ответ: 7; 4
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Thanks 1
РязанцевВаня
(y-5)(y-6)=2
(y-5)*y=2+6
(y-5)*y=8
y*y=8+5
y*y=13
y=
y=3,605551275463989
0 votes
Thanks 0
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Answers & Comments
y^2-11y+28=0
D=11^2-4*28=121-112=9
y1=(11+3)/2=7
y2=(11-3)/2=4
Ответ: 7; 4
(y-5)*y=2+6
(y-5)*y=8
y*y=8+5
y*y=13
y=
y=3,605551275463989