Ответ:
(sina+sin3a)×sin6a
1/2((cos(a-b)-cos(a+b))
1/2(cos2a-cos4a)×sin6a
1/2((sin(a+b)-sin(a-b))
1) 1/2sin8a-sin4a
2) 1/2sin10a-sin2a
sin8a+sin4a+cos3a-cos9a
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
(sina+sin3a)×sin6a
1/2((cos(a-b)-cos(a+b))
1/2(cos2a-cos4a)×sin6a
1/2((sin(a+b)-sin(a-b))
1) 1/2sin8a-sin4a
2) 1/2sin10a-sin2a
sin8a+sin4a+cos3a-cos9a