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Mora1
@Mora1
August 2022
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Запишите многочлен в стандартном виде (х^2-3х+1)*(х^2-3х-3)
(распишите подробно, пожалуйста)
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scoundrel07
(х²-3х +1)·(х²-3х -3) =
= х²·х² + х²·(-3х) + х²·(-3) -3х·х² - 3х·(-3х) - 3х·(-3) +1·х² + 1·(-3х) + 1·(-3) =
= х⁴ -
3х³
-3х² -
3х³
+9х² + 9х +х² -3х -3
=
= х⁴ - 6х³ + 7х² +6х - 3.
1 votes
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Answers & Comments
= х²·х² + х²·(-3х) + х²·(-3) -3х·х² - 3х·(-3х) - 3х·(-3) +1·х² + 1·(-3х) + 1·(-3) =
= х⁴ - 3х³ -3х² - 3х³ +9х² + 9х +х² -3х -3 =
= х⁴ - 6х³ + 7х² +6х - 3.