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shabanovaolga
@shabanovaolga
August 2022
1
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Запишите разложение бинома:
(х+1)^8
(а-1)^9
(y+2)^6
(2b+3)^5
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Answers & Comments
LyubaAlexandorovna
1. (2*b+3)^5=32*b^5+240*b^4+720*b^3+1080*b^2+810*b+243
2. (x+1)^8=x^8+8*x^7+28*x^6+56*x^5+70*x^4+56*x^3+28*x^2+8*x+1
3. (a-1)^9=a^9-9*a^8+36*a^7-84*a^6+126*a^5-126*a^4+84*a^3-36*a^2+9*a-1
4. (y+2)^6=y^6+12*y^5+60*y^4+160*y^3+240*y^2+192*y+64
18 votes
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Answers & Comments
2. (x+1)^8=x^8+8*x^7+28*x^6+56*x^5+70*x^4+56*x^3+28*x^2+8*x+1
3. (a-1)^9=a^9-9*a^8+36*a^7-84*a^6+126*a^5-126*a^4+84*a^3-36*a^2+9*a-1
4. (y+2)^6=y^6+12*y^5+60*y^4+160*y^3+240*y^2+192*y+64