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byjuly
@byjuly
August 2022
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Запишите в виде многочлена стандартного вида:
3(4a-1)-(12a+3)+2a
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Antonich
3(4a-1)-(12a+3)+2a=12a-3-12a-3+2a= -6+2a=2a-6=2(a-3)
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ollllolololol
3(4a-1)-(12a+3)+2a
12а-3-12а-3+2а
-6+2а
2*(-3+а)
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Antonich
ещё за скобки в конце можно вынести 2
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Answers & Comments
12а-3-12а-3+2а
-6+2а
2*(-3+а)