Ответ:
3) 4)
Объяснение:
Δl1=2.75 Δl2=2
===
min Δl1=(2*k+1)*(l/2)
max Δl2=k*l ---> k=Δl2/l
2.75=(2*2.5/l+1)*(l/2)
l=0.5 мкм
=====================
k=2 α=30 l=500*10^-9 м L=0.03 м
d*sinα=k*l
d=1/No
No=sinα/(k*l)=0.5/(2*500*10^-9)=0.5*10^6
N=L*No=0.03*0.5*10^6=15000
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Ответ:
3) 4)
Объяснение:
Δl1=2.75 Δl2=2
===
min Δl1=(2*k+1)*(l/2)
max Δl2=k*l ---> k=Δl2/l
2.75=(2*2.5/l+1)*(l/2)
l=0.5 мкм
=====================
k=2 α=30 l=500*10^-9 м L=0.03 м
===
d*sinα=k*l
d=1/No
No=sinα/(k*l)=0.5/(2*500*10^-9)=0.5*10^6
N=L*No=0.03*0.5*10^6=15000
================================