z=cos (2x^2-y) найти dz. Created by 4577. matematika-ru

z=cos (2x^2-y) найти dz...

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August 2022 1 10 Report

z=cos (2x^2-y) найти dz

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$z=cos(2x^2-y)\\\\dz=z'_{x}dx+z'_{y}dy\\\\dz=-sin(2x^2-y)\cdot 4x\cdot dx-sin(2x^2-y)\cdot (-1)\cdot dy\\\\dz=-4x\cdot sin(2x^2-y)dx+sin(2x^2-y)dy\\\\dz=sin(2x^2-y)\cdot (-4x\, dx+dy)$

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