1,425 х
Fe2O3+2Al-->2Fe+Al2O3
х=2,85
n(Fe2O3)=228:160=1,425моль
m(Fe)=2,85×56=159,6г
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1,425 х
Fe2O3+2Al-->2Fe+Al2O3
х=2,85
n(Fe2O3)=228:160=1,425моль
m(Fe)=2,85×56=159,6г