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katafotik48
@katafotik48
August 2021
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Sin29/√(1-sin(90-58))=sin29/√(1-cos(2*29))=sin29/(√2sin²29)=1/√2=√2/2
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Sin29/√(1-sin(90-58))=sin29/√(1-cos(2*29))=sin29/(√2sin²29)=1/√2=√2/2