f(x) = x² - 2x + 1
f'(x) = (x²)' - 2 * x' + 1' = 2x - 2 * 1 + 0 = 2x - 2
f'(0) = 2 * 0 - 2 = - 2
f'(0) = - 2
f'(2) = 2 * 2 - 2 = 2
f'(2) = 2
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f(x) = x² - 2x + 1
f'(x) = (x²)' - 2 * x' + 1' = 2x - 2 * 1 + 0 = 2x - 2
f'(0) = 2 * 0 - 2 = - 2
f'(0) = - 2
f'(2) = 2 * 2 - 2 = 2
f'(2) = 2