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slavakostyl
@slavakostyl
November 2021
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Знайдіть кут між векторами а(-2;2√3) і в(3;-√3)
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Kазак
Розв'язання додано. 150°.
5 votes
Thanks 11
valenivan
Verified answer
Скалярное произведение векторов
a·b = |a|*|b|*cos(β)
cos(β) = a·b/(|a|*|b|)
a·b = -2*3 - 2√3*√3 = -6 -6 = -12
|a| = √(2² + (2√3)²) = √(4 + 4*3) = √16 = 4
|b| = √(3² + (-√3)²) = √(9 + 3) = √12 = 2√3
cos(β) = -12/(4*2√3) = -3/(2√3) = -√3/2
β = arccos(-√3/2) = 5π/6 = 150°
10 votes
Thanks 15
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Answers & Comments
Verified answer
Скалярное произведение векторовa·b = |a|*|b|*cos(β)
cos(β) = a·b/(|a|*|b|)
a·b = -2*3 - 2√3*√3 = -6 -6 = -12
|a| = √(2² + (2√3)²) = √(4 + 4*3) = √16 = 4
|b| = √(3² + (-√3)²) = √(9 + 3) = √12 = 2√3
cos(β) = -12/(4*2√3) = -3/(2√3) = -√3/2
β = arccos(-√3/2) = 5π/6 = 150°