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Dora0
@Dora0
July 2022
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Знайдiть кути ромба, периметр якого дорiвнюе 36см, а площа 18см2
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KuOV
Verified answer
A = P/4 = 36/4 = 9 (см) - сторона ромба
S = a² · sinα
18 = 81 · sinα
sinα = 18/81 = 2/9
α = arcsin (2/9) и α = 180° - arcsin(2/9)
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Answers & Comments
Verified answer
A = P/4 = 36/4 = 9 (см) - сторона ромбаS = a² · sinα
18 = 81 · sinα
sinα = 18/81 = 2/9
α = arcsin (2/9) и α = 180° - arcsin(2/9)