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timoshka400
@timoshka400
July 2022
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Знайдіть перший член і знаменник геометричної прогресії кщо b2+b3=30 b4-b2=90
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dydx
Verified answer
B2+b3=b1q+b1q^2=b1(q+q^2)=30;
b4-b2=b1q^3-b1q=b1(q^3-q)=90;
(q+q^2)
----------- = 30/90;
(q^3-q)
(1+q)/((q-1)(q+1)) = 1/3;
1/(q-1)=1/3 => q-1=3; q=4.
b1(q+q^2)=30 => b1=30/20=1,5
Ответ: q=4; b1=1,5
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NNNLLL54
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Answers & Comments
Verified answer
B2+b3=b1q+b1q^2=b1(q+q^2)=30;b4-b2=b1q^3-b1q=b1(q^3-q)=90;
(q+q^2)
----------- = 30/90;
(q^3-q)
(1+q)/((q-1)(q+1)) = 1/3;
1/(q-1)=1/3 => q-1=3; q=4.
b1(q+q^2)=30 => b1=30/20=1,5
Ответ: q=4; b1=1,5
Verified answer