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@gfjfjdbrhdjjd
March 2022
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знайдiть рiвняння дотичноï до графiка функцiï f(x)=3x^2-x^3 у точцi з абсцисою x°=-2 (там внизу нолик)
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gfjfjdbrhdjjd
March 2022 | 0 Ответы
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gfjfjdbrhdjjd
March 2022 | 0 Ответы
znajdit rivnyannya dotichnoi do grafika funkcii fxx2 4x 10yaka paralelna pryam
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