Ответ:

Объяснение:

3x³-2y³-6x²y²+xy=

=3(2/3)³-2(1/2)³-6(2/3)²*(1/2)²+2/3*1/2=

=3*8/27 – 2*1/8 -6*4/9*1/4 +2/6=

=8/9-1/4-6* 4/36+2/6=

=8/9-1/4-6*1/9+1/3=

=8/9-1/4-2/3+1/3=

8/9-1/4-1/3=

(32-9-12)/36= 11/36

3х³-2у³-6х²у²+ху=3х²(х-2у²)+у*(-2у²+х)=(х-2у²)(3х²+у) → (2/3-2*(1/2)²)*(3*(2/3)²+1/2)=(2/3-2*1/4)*(3*4/9+1/2)=(2/3-1/2)*(4/3+1/2)=((4-3)/6)*((8+3)/6)=1/6*11/6=11/36