Знайти критичні точки f(x)=2x^3-15x^2+36x. Created by Milashka0810. algebra-ru

Знайти критичні точки f(x)=2x^3-15x^2+36x...

Milashka0810 @Milashka0810

July 2022 1 16 Report

Знайти критичні точки
f(x)=2x^3-15x^2+36x

Answers & Comments

Medved23

Критические точки - те точки, в которых производная f'(x) не существует или равна нулю.

Ищем производную и приравниваем ее к нулю.

$f(x)=2x^3-15x^2+36x;\\\\f'(x)=(2x^3-15x^2+36x)'=(2x^3)'-(15x^2)'+(36x)'=6x^2-30x+36=0.\\\\6x^2-30x+36=0|:6\\\\x^2-5x+6=0\\\\\left \{ {{x_1x_2=6} \atop {x_1+x_2=5}} \right. \Rightarrow x_1=2, x_2=3$

Критические точки - $x =2$ и $x=3$ .

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vstaviti slova v tekst 70 b

vkazhit rechovinu yaku mozhna vikoristati dlya viyavlennya glicerolu

Choose the correct word where, which, who, when, whose, to complete the sentence...

Put as many questions as you can to the following sentence Great Britain is a co...

Put as many questions as you can to the following sentence Great Britain is a co...

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pershe zavdannya dopomozhit7494a40ce256e03e877ea17d4e06b7da 81585

shire sercechiste sumlinnyahist do muzikishkidliva zvichka utvoriti rechennya z cimi

dopomozhit 1 vprava 10 baliv

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