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yulialexandrova
@yulialexandrova
October 2021
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Знайти масову частку Феруму у таких сполуках: FeO, Fe2O3, Fe3O4
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Alhimica
W(Fe)=M(Fe)/M(FeO)=56/72≈0.78≈78%
w(Fe)=M(Fe)*2/M(Fe2O3)=56*2/160=0.7=70%
w(Fe)=M(Fe)*3/M(Fe3O4)=56*3/232≈0.724≈72.4%
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Answers & Comments
w(Fe)=M(Fe)*2/M(Fe2O3)=56*2/160=0.7=70%
w(Fe)=M(Fe)*3/M(Fe3O4)=56*3/232≈0.724≈72.4%