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RASSPUTIN
@RASSPUTIN
July 2022
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знайти масову частку хлороводню у вихідному розчинні .
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dec77cat
M(CaCO₃)=25 г
m(p)=200 г
CaCO₃ + 2HCl = CaCl₂ + H₂O + CO₂
m(HCl)/2M(HCl)=m(CaCO₃)/M(CaCO₃)
маса хлороводню
m(HCl)=2M(HCl)m(CaCO₃)/M(CaCO₃)
и
m(HCl)=m(p)w
m(p)w=2M(HCl)m(CaCO₃)/M(CaCO₃)
масова частка хлороводню
w=2M(HCl)m(CaCO₃)/{m(p)M(CaCO₃)}
w=2*36,5г/моль*25г/{200г*100,1г/моль}=0,091 (9,1%)
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Answers & Comments
m(p)=200 г
CaCO₃ + 2HCl = CaCl₂ + H₂O + CO₂
m(HCl)/2M(HCl)=m(CaCO₃)/M(CaCO₃)
маса хлороводню
m(HCl)=2M(HCl)m(CaCO₃)/M(CaCO₃)
и
m(HCl)=m(p)w
m(p)w=2M(HCl)m(CaCO₃)/M(CaCO₃)
масова частка хлороводню
w=2M(HCl)m(CaCO₃)/{m(p)M(CaCO₃)}
w=2*36,5г/моль*25г/{200г*100,1г/моль}=0,091 (9,1%)