f(x) = (x - 2)^3
f'(x) = 3(x-2)'(x-2)^2 = 3(x - 2)^2
y = tg(3 - 2x)
y' = (3 - 2x)' (tg(3 - 2x))' = -2 × 1/cos^2 (3 - 2x) = -2/cos^2 (3 - 2x)
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f(x) = (x - 2)^3
f'(x) = 3(x-2)'(x-2)^2 = 3(x - 2)^2
y = tg(3 - 2x)
y' = (3 - 2x)' (tg(3 - 2x))' = -2 × 1/cos^2 (3 - 2x) = -2/cos^2 (3 - 2x)