1)3√30-2√42 ---------------- √45-√28 2) 7-3√2 --------- + 7+3√2 / 7-3√2 7+3√2 /-знак деления дробью. Created by Ilonkaaa. algebra-ru

-знак деления дробью...

Rechnung

Verified answer

$\frac{3\sqrt{30}-2\sqrt{42}}{\sqrt{45}-\sqrt{28}}=\frac{3\sqrt{6}\sqrt{5}-2\sqrt{6}\sqrt{7}}{3\sqrt{5}-2\sqrt{7}}=\frac{\sqrt{6}(\sqrt{5}-2\sqrt{7})}{3\sqrt{5}-2\sqrt{7}}=\sqrt{6}$

$\frac{7-3\sqrt{2}}{7+3\sqrt{2}}+\frac{7+3\sqrt{2}}{7-3\sqrt{2}}=\\\\=\frac{(7-3\sqrt{2})^2+(7+3\sqrt{2})^2}{(7+3\sqrt{2})(7-3\sqrt{2})}=\frac{(49-42\sqrt{2}+18)+(49+42\sqrt{2}+18)}{49-18}=\\\\=\frac{134}{31}=4\frac{10}{31}$

1 votes Thanks 5

dtnth

Verified answer

$\frac{3\sqrt{30}-2\sqrt{42}}{\sqrt{45}-\sqrt{28}}=\\\\ \frac{3\sqrt{5*6}-2\sqrt{7*6}}{\sqrt{9*5}-\sqrt{4*7}}=\\\\ \frac{3\sqrt{5}*\sqrt{6}-2\sqrt{7}*\sqrt{6}}{\sqrt{9}*\sqrt{5}-\sqrt{4}*\sqrt{7}}=\\\\ \frac{\sqrt{6}(3\sqrt{5}-2\sqrt{7})}{3\sqrt{5}-2\sqrt{7}}=\\\\ \sqrt{6}$

$\frac{7-3\sqrt{2}}{7+3\sqrt{2}}+\frac{7+3\sqrt{2}}{7-3\sqrt{2}}=\\\\ \frac{(7-3\sqrt{2})^2}{(7+3\sqrt{2})(7-3\sqrt{2})}+\frac{(7+3\sqrt{2})^2}{(7-3\sqrt{2})(7+3\sqrt{2})}=\\\\ \frac{(7-3\sqrt{2})^2+(7+3\sqrt{2})^2}{(7-3\sqrt{2})(7+3\sqrt{2})}=\\\\ \frac{49-42\sqrt{2}+18+49+42\sqrt{2}+18}{49-18}=\\\\ \frac{134}{31}$

0 votes Thanks 5

Answers & Comments

Verified answer

Verified answer

kak najti dlinu vektora znaya ego koordinaty rebyat esli ne slozhno luchshe formulo

najdite ploshad pravilnogo shestiugolnika storona kotorogo ravno koren iz 52ef2f2dcf3b1bb897f0ca7d447fa9a85 47621

vychislite cos2a esli cosa 02 pomogite pozhalujsta

ispolzuya odnovremenno dva podemnyh krana barzhu razgruzili za 6ch za kakoe vre

rebyat tut zadanie uprostite vyrozhenie i vse s kvadratnymi kornyamiya ih budu sok

1115 004 1495 24drob5 2 1drob95682

skolko storon imeet pravilnyj mnogougolnikesli centralnyj ugolsootvetstvuyu

рекомендуемые вопросы

Helpful Links

Helpful Social