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readyreally
@readyreally
May 2022
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z(z-10)>(3-z)²
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zehrajumabaeva
[tex]z(z - 10) > (3 - 2) [/tex][tex] {z}^{2} - 10z > {1}^{2} [/tex][tex] {z}^{2} - 10z = > 1[/tex][tex] {z}^{2} - 10 - 1 > 0 \\ {z}^{2} -1 0z - 1 = 0 \\ z = 5 + \sqrt{26} \\ z = 5 - \sqrt{26} [/tex][tex](z - (5 - \sqrt{26} )) \times (z - (5 + \sqrt{26} ) > 0[/tex][tex] \binom{2 - 5 - \sqrt{26 > 0} }{2 - 5 + \sqrt{26 > 0} } [/tex]
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readyreally
дай свой Вк пожалуйста
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