0.125 ^x=2*4^x....... Created by sinusoida2000. algebra-ru

0.125 ^x=2*4^x...

NNNLLL54

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$0,125^{x}=2\cdot 4^{x}\\\\0,125= \frac{125}{1000} =\frac{1}{8}= \frac{1}{2^3} =2^{-3}\\\\(2^{-3})^{x}=2\cdot (2^2)^{x}\\\\2^{-3x}=2^{2x+1}\\\\-3x=2x+1\\\\-5x=1\\\\x=-\frac{1}{5}$

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Kixcertborn2

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О,Ваше задание решено!Ответ с подробным решением, найдёте Вы во вложениях.

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