[tex]\displaystyle\bf\\25^{3-x} =\frac{1}{5} \\\\\\\Big(5^{2} \Big)^{3-x} =5^{-1} \\\\\\5^{6-2x} =5^{-1} \\\\\\6-2x=-1\\\\\\-2x=-1-6\\\\\\-2x=-7\\\\\\\boxed{x=3,5}[/tex]
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[tex]\displaystyle\bf\\25^{3-x} =\frac{1}{5} \\\\\\\Big(5^{2} \Big)^{3-x} =5^{-1} \\\\\\5^{6-2x} =5^{-1} \\\\\\6-2x=-1\\\\\\-2x=-1-6\\\\\\-2x=-7\\\\\\\boxed{x=3,5}[/tex]