[tex]\displaystyle 1)5^-^4*5^2=5^-^2=\frac{1}{5^2}=\frac{1}{25}=0,04\\ \\2)12^-^3:12^-^4=12^-^3^+^4=12^1=12\\\\3)(3^-^1)^-^3=3^3=27[/tex]

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Ответ:

Объяснение:

[tex]5^{-4} *5^{2} =5^{-4+2} =5^{-2}=\frac{1}{25}[/tex]

[tex]12^{-3}:12^{-4} =12^{-3-(-4)}=12^{-3+4}=12^{1}=12[/tex]

[tex](3^{-1})^{-3}=3^{-1*(-3)} =3^{3}=27[/tex]