Verified answer

[tex]\displaystyle\bf\\1)\\\\\Big(a^{-5}\Big)^{4} \cdot a^{22} =a^{-20} \cdot a^{22} =a^{-20+22} =a^{2} \\\\\\2)\\\\0,4x^{5} y^{-8} \cdot 50x^{-5}y^{9} =0,4\cdot 50\cdot x^{5-5} \cdot y^{-8+9}=20\cdot x^{0} \cdot y =\\\\\\=20\cdot 1 \cdot y=20y[/tex]

Решение на фотографии