у = kx + b
А ( 2 ; - 1 )
В ( - 2 ; - 3 )
[tex]\displaystyle\bf\\ + \left \{ {{2k + b = - 1} \atop { - 2k + b = - 3 }} \right. \\ \\ b + b = - 3 - 1 \\ 2b = - 4 \\ b = - 4 \div 2 \\ b = - 2 \\ \\ 2k - 2 = - 1 \\ 2k = - 1 + 2 \\2 k = 1 \\ k = \div 2 \\ k = 0.5[/tex]
Ответ: у = 0,5х - 2
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у = kx + b
А ( 2 ; - 1 )
В ( - 2 ; - 3 )
[tex]\displaystyle\bf\\ + \left \{ {{2k + b = - 1} \atop { - 2k + b = - 3 }} \right. \\ \\ b + b = - 3 - 1 \\ 2b = - 4 \\ b = - 4 \div 2 \\ b = - 2 \\ \\ 2k - 2 = - 1 \\ 2k = - 1 + 2 \\2 k = 1 \\ k = \div 2 \\ k = 0.5[/tex]
Ответ: у = 0,5х - 2