[tex](x-4)(x-y)[/tex]
[tex]x^2-xy-4x+4y=x(x-y)-4(x-y)=(x-4)(x-y)[/tex]
[tex]\displaystyle x^2-xy-4x+4y=x(x-y)-4(x-y)=(x-y)(x-4)[/tex]
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Ответ:
[tex](x-4)(x-y)[/tex]
Объяснение:
[tex]x^2-xy-4x+4y=x(x-y)-4(x-y)=(x-4)(x-y)[/tex]
[tex]\displaystyle x^2-xy-4x+4y=x(x-y)-4(x-y)=(x-y)(x-4)[/tex]