(2sin^2 L - 1)/(1 - 2cos^2L)
= (2(1-cos²α)-1) / (1-2cos²α ) = (2-2cos²α-1) / (1-2cos²α ) = (1-2cos²α ) / (1-2cos²α ) = 1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
= (2(1-cos²α)-1) / (1-2cos²α ) = (2-2cos²α-1) / (1-2cos²α ) = (1-2cos²α ) / (1-2cos²α ) = 1