1) а2-5аб-б2- а2+б2 =
2) (2у2+8у-11)+(3у2-6у+3)=
3) (3x+1)+(-3x2-3x+1)=
4) (а+3b)-(3a-3b)=
5) (9a3-a-3)+(9a2+a-4)=
помогите решить пж
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