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Miykka
@Miykka
June 2022
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1 + cos 2x + 2 cos x * cos 3x = 0
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rima134
1+cos2x+2cosx*cos3x=0 1+cos2x+2(cos(x+3x)+cos(x-3x))/2=0 1+cos2x+cos4x+cos2x=0 1+2cos2x+2cos^2(2x)-1=0 2cos^2(2x)+2cos2x=0
cos2x(cos2x-1=0 cos2x=0 2x=pi/2+pi*n x=pi/4+pi/2*n
cos2x-1=0 cos2x=1 2x=0+2pi*n x=pi*n n (- Z
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Answers & Comments
cos2x(cos2x-1=0 cos2x=0 2x=pi/2+pi*n x=pi/4+pi/2*n
cos2x-1=0 cos2x=1 2x=0+2pi*n x=pi*n n (- Z