Вычислите интегралы: 1. In(y)dy/y^2 2. dx/(корень x*y)-x 3. dz/1-sinz. Created by galinacyzz. matematika-ru

1-sinz...

galinacyzz @galinacyzz

July 2022 1 19 Report

Вычислите интегралы:
1. In(y)dy/y^2
2. dx/(корень x*y)-x
3. dz/1-sinz

Answers & Comments

NNNLLL54

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$1)\; \; \int \frac{lny\cdot dy}{y^2}=[\, u=lny\; ,\; du=\frac{dy}{y}\; ,\; dv=\frac{dy}{y^2}\; ,\; v=\int \frac{dy}{y^2}=\int y^{-2}dy=\\\\= \frac{y^{-1}}{-1}=-\frac{1}{y}\, ]=[\, \int u\, dv=uv-\int v\, du]=\\\\=- \frac{lny}{y}+\int \frac{dy}{y^2}=-\frac{lny}{y}-\frac{1}{y} +C\\\\3)\; \; \int \frac{dz}{1-sinz}=[\, t=tg\frac{z}{2},\; sinz=\frac{2t}{1+t^2}\; ,\; dz=\frac{2\, dt}{1+t^2}\, ]=\\\\=\int \frac{2\, dt}{(1+t^2)\cdot (1-\frac{2t}{1+t^2})}=2\int \frac{dt}{t^2-2t+1}=2\int \frac{dt}{(t-1)^2} =2\cdot \frac{(t-1)^{-1}}{-1}=$

$=- \frac{2}{t-1}+C=- \frac{2}{tg\frac{x}{2}-1}+C\\\\\\\star \; \; \int (ax+b)^{n}= \frac{1}{a}\cdot \frac{(ax+b)^{n+1}}{n+1} +C\; \; ,\; \; ax+b=t-1\; ,\; a=1\; ,\; n=-2$

P.S. Во 2 примере ошибка в условии.

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