Ответ:
1) (x-8)^2-x(x+6)=-2
x^2-16x+64-x^2-6x=-2
-22x+64=-2
-22x=-2-64
-22x=-66
x=3
2) (x+7)=(x-3)(x+3)
x+7=x^2-9
x+7-x^2+9=0
x+16-x^2=0
-x^2+x+16=0
x^2-x-16=0
a=1; b=-1; c=-16
x=-(-1)±√(-1)^2-4×1×(-16)/2×1
x=1±√1+64/2
x2=1+√65/2
x1=1-√65/2
3) (2x+1)-(2x-1)×(2x+3)=0
2x+1-(4x^2+6x-2x-3)=0
2x+1-(4x^2+4x-3)=0
2x+1-4x^2-4x+3=0
-2x+4-4x^2=0
x-2+2x^2=0
2x^2+x-2=0
a=2; b=1; c=-2
x=-1±√1^2-4×2×(-2)/2×2
x=-1±√1+16/4
x2= -1+√17/4
x1= -1-√17/4
4) x(x-2)-(x+5)^3=35
x^2-2x-(x^3+15x^2+75x+125)=35
x^2-2x-x^3-15x^2-75x-125=35
-14x^2-77x-x^3-125=35
-14x^2-77x-x^3-125-35=0
-x^3-14x^2-77x-160=0
-x^3-5x^2-9x^2-45x-32x-160=0
-x^2×(x+5)-9x×(x+5)-32(x+5)=0
-(x+5)×(x^2+9x+32)=0
(x+5)(x^2+9x+32)=0
x+5=0
x^2+9x+32=0
x=-5
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Answers & Comments
Ответ:
1) (x-8)^2-x(x+6)=-2
x^2-16x+64-x^2-6x=-2
-22x+64=-2
-22x=-2-64
-22x=-66
x=3
2) (x+7)=(x-3)(x+3)
x+7=x^2-9
x+7-x^2+9=0
x+16-x^2=0
-x^2+x+16=0
x^2-x-16=0
a=1; b=-1; c=-16
x=-(-1)±√(-1)^2-4×1×(-16)/2×1
x=1±√1+64/2
x2=1+√65/2
x1=1-√65/2
3) (2x+1)-(2x-1)×(2x+3)=0
2x+1-(4x^2+6x-2x-3)=0
2x+1-(4x^2+4x-3)=0
2x+1-4x^2-4x+3=0
-2x+4-4x^2=0
x-2+2x^2=0
2x^2+x-2=0
a=2; b=1; c=-2
x=-1±√1^2-4×2×(-2)/2×2
x=-1±√1+16/4
x2= -1+√17/4
x1= -1-√17/4
4) x(x-2)-(x+5)^3=35
x^2-2x-(x^3+15x^2+75x+125)=35
x^2-2x-x^3-15x^2-75x-125=35
-14x^2-77x-x^3-125=35
-14x^2-77x-x^3-125-35=0
-x^3-14x^2-77x-160=0
-x^3-5x^2-9x^2-45x-32x-160=0
-x^2×(x+5)-9x×(x+5)-32(x+5)=0
-(x+5)×(x^2+9x+32)=0
(x+5)(x^2+9x+32)=0
x+5=0
x^2+9x+32=0
x=-5