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pkrapivin
@pkrapivin
June 2022
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MrLyanda
G(x)=2/5 x^5-4x^3
g'(x)=2/5 *5*x^4-4*3*x^2=2x^4-12x^2
в общем случае:
f(x)=x^y
f'(x)=y*x^(y-1)
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Answers & Comments
g'(x)=2/5 *5*x^4-4*3*x^2=2x^4-12x^2
в общем случае:
f(x)=x^y
f'(x)=y*x^(y-1)