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pkrapivin
@pkrapivin
August 2021
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дана арифметическая прогрессия (an) : -12;1;14...Найдите сумму первых восьми членов прогрессии
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KatDogdikova14
-12, 1, 14,...
а1=-12.
d=a2-a1=1-(-12)=1+12=13. 67
2*a1+d*(n-1) 2*a1+7*d 2*(-12)+7*13 (91-24)*8 67*8 536
S8=------------------- *n=---------------------*8=------------------*8=--------------- =-----------= ----- = 2 2 2 2 2 2
=268.
2 votes
Thanks 1
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Answers & Comments
а1=-12.
d=a2-a1=1-(-12)=1+12=13. 67
2*a1+d*(n-1) 2*a1+7*d 2*(-12)+7*13 (91-24)*8 67*8 536
S8=------------------- *n=---------------------*8=------------------*8=--------------- =-----------= ----- = 2 2 2 2 2 2
=268.