Ответ:
Mr(BaO)=137+16=153,
Mr(Fe203)=112+48=160
Mr(NH4*2SO4)=14+4*2+32+64=36+96=132
Mr(FeOH3)=56+16*3+3=56+51=107
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Ответ:
Mr(BaO)=137+16=153,
Mr(Fe203)=112+48=160
Mr(NH4*2SO4)=14+4*2+32+64=36+96=132
Mr(FeOH3)=56+16*3+3=56+51=107