Объяснение:
1.
∫² (1-1/x²)dx= ∫1dx -∫1/x² dx=(x+1/x )|²=
¹ ¹
=2+1/2-(1+1/1)=2+1/2-2=1/2=0,5
2.
∫⁴ (3/(2√(3x+4)) -x)dx =∫3/(2√(3x+4))-∫xdx=
`¹
=√(3x+4) -x²/2 |⁴ =
= √(3•4+4)-4²/2 -(√(3•(-1)+4) -(-1)²/2=
=√16 -8-√1 +1/2=4-8-1+0,5= -4,5
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Объяснение:
1.
∫² (1-1/x²)dx= ∫1dx -∫1/x² dx=(x+1/x )|²=
¹ ¹
=2+1/2-(1+1/1)=2+1/2-2=1/2=0,5
2.
∫⁴ (3/(2√(3x+4)) -x)dx =∫3/(2√(3x+4))-∫xdx=
`¹
=√(3x+4) -x²/2 |⁴ =
`¹
= √(3•4+4)-4²/2 -(√(3•(-1)+4) -(-1)²/2=
=√16 -8-√1 +1/2=4-8-1+0,5= -4,5