Ответ:
[tex]10[/tex]
Объяснение:
[tex]3x+\frac{1}{x}=-4\ \ \ |()^2\\\\9x^2+2\cdot 3x\cdot \frac{1}{x}+\frac{1}{x^2}=16\\\\9x^2+6+\frac{1}{x^2}=16\\\\9x^2+\frac{1}{x^2}=16-6\\\\9x^2+\frac{1}{x^2}=10[/tex]
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Verified answer
Ответ:
[tex]10[/tex]
Объяснение:
[tex]3x+\frac{1}{x}=-4\ \ \ |()^2\\\\9x^2+2\cdot 3x\cdot \frac{1}{x}+\frac{1}{x^2}=16\\\\9x^2+6+\frac{1}{x^2}=16\\\\9x^2+\frac{1}{x^2}=16-6\\\\9x^2+\frac{1}{x^2}=10[/tex]
(3x+1/x)^2=16
(9x^2)+2*3x*1/x+(1/x)^2=16
9x^2+1/x^2=10
Вот:….