△CBD~△ABC (по двум углам)
BC/DB =AB/BC => BC^2 =AB*DB =3.6*AB
AB^2 =BC^2 +AC^2 (т Пифагора)
AB^2 -3.6*AB -64 =0
AB =1.8 +√(1.8^2 +64) =10 (AB>0)
BC =√(3.6*AB) =√36 =6 (см)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
△CBD~△ABC (по двум углам)
BC/DB =AB/BC => BC^2 =AB*DB =3.6*AB
AB^2 =BC^2 +AC^2 (т Пифагора)
AB^2 -3.6*AB -64 =0
AB =1.8 +√(1.8^2 +64) =10 (AB>0)
BC =√(3.6*AB) =√36 =6 (см)