(8х-3)/7-(3х+1)/10=2 помогите решить :*. Created by irinapovarnicyna. algebra-ru

10=2 помогите решить :*...

irinapovarnicyna @irinapovarnicyna

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(8х-3)/7-(3х+1)/10=2 помогите решить :*

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Dоnnа

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$\frac{(8x-3)}{7} - \frac{(3x+1)}{10} =2 \\ \\ 10(8x-3)-7(3x+1)=140 \\ 80x-30-21x-7=140 \\ 59x-30-7=140 \\ 59x-37=140 \\ 59x=140+37 \\ 59x=177 \\ x=177:59 \\ x=3$

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