Ответ:

x + 2 > 1, x ≥ 0

x > 3, x ≥ 0

x ∈ (3; +∞)

2) 5x + 1 < 81, x ≥ 0

5x < 81 - 1, x ≥ 0

5x < 80, x ≥ 0

x < 16, x ≥ 0

x ∈ [0; 16)

3) x² - |x| + 1 > 5 - |x|

x² - |x| + |x| > 5 - 1

x² > 4

|x| > 2

x > 2, x ≥ 0

-x > 2, x < 0

x ∈ (2; +∞)

x ∈ (-∞; -2)

x ∈ (2; +∞) U (-∞; -2)