Ответ:
дано
m(CnH2n) = 10.5 g
V(HBr) = 5.6 L
--------------------
CnH2n - ?
10.5 5.6
CnH2n + HBr-->CnH2n+1Br
14n 22.4
M(CnH2n) = 12n+2n = 14n g/mol
10.5 / 14 = 5.6 / 22.4
14n = 10.5 * 22.4 / 5.6
14n = 42
n = 3
C3H6
ответ С3Н6
Объяснение:
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Answers & Comments
Ответ:
дано
m(CnH2n) = 10.5 g
V(HBr) = 5.6 L
--------------------
CnH2n - ?
10.5 5.6
CnH2n + HBr-->CnH2n+1Br
14n 22.4
M(CnH2n) = 12n+2n = 14n g/mol
10.5 / 14 = 5.6 / 22.4
14n = 10.5 * 22.4 / 5.6
14n = 42
n = 3
C3H6
ответ С3Н6
Объяснение: