[tex] \displaystyle \frac{( {3}^{15} + {3}^{13}) \cdot {2}^{9} }{( {3}^{14} \cdot {3}^{12}) \cdot1024 } = \boldsymbol{ \frac{(3 \cdot {3}^{14} + 3 \cdot {3}^{12}) \cdot \not{2}^{9} }{( {3}^{14} \cdot {3}^{12} ) \cdot \not{2}^{9} \cdot2} = \frac{3( {3}^{14} + {3}^{12}) }{( {3}^{14} + {3}^{12} ) \cdot2} = \frac{3}{2} } \\ [/tex]
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[tex] \displaystyle \frac{( {3}^{15} + {3}^{13}) \cdot {2}^{9} }{( {3}^{14} \cdot {3}^{12}) \cdot1024 } = \boldsymbol{ \frac{(3 \cdot {3}^{14} + 3 \cdot {3}^{12}) \cdot \not{2}^{9} }{( {3}^{14} \cdot {3}^{12} ) \cdot \not{2}^{9} \cdot2} = \frac{3( {3}^{14} + {3}^{12}) }{( {3}^{14} + {3}^{12} ) \cdot2} = \frac{3}{2} } \\ [/tex]
Ответ: С) 3/2