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bumer7
@bumer7
July 2022
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упростите выражение ctg9пи/4+sin37пи/12-cos7пи/12 c подробным решением!!!!!
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oganesbagoyan
Verified answer
Ctq9π/4 +sin37π/12 -cos7π/12 =ctq(2π+π/4) +sin(2π+π+π/12) - cos7π/12 =
ctqπ/4 - sin(π+π/12) - cos(π/2+π/12) =1 -sinπ/12 +sinπ/12 =
1.
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Answers & Comments
Verified answer
Ctq9π/4 +sin37π/12 -cos7π/12 =ctq(2π+π/4) +sin(2π+π+π/12) - cos7π/12 =ctqπ/4 - sin(π+π/12) - cos(π/2+π/12) =1 -sinπ/12 +sinπ/12 = 1.