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aleksand088
@aleksand088
July 2022
1
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2√3-4√3 sin^2 23pi/12 с решением
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Zhiraffe
=2√3*(1-2* sin^2 23pi/12)=
= 2√3*cos(2*23pi/12)=
= 2√3* √3/2=3
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Answers & Comments
= 2√3*cos(2*23pi/12)=
= 2√3* √3/2=3