х²-12х+20=0
D=b²-4ac=144-4×20=144-80=64
x1=(-b+√D)/2a = (12+8)/2 = 20/2 = 10
x2= (-b-√D)/2a = (12-8)/2= 4/2=2
Відповідь: х1=10, х2=2
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х²-12х+20=0
D=b²-4ac=144-4×20=144-80=64
x1=(-b+√D)/2a = (12+8)/2 = 20/2 = 10
x2= (-b-√D)/2a = (12-8)/2= 4/2=2
Відповідь: х1=10, х2=2