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Asagami
@Asagami
August 2022
1
8
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Решите пожалуйста математику :-(
1) Вычислить расстояние между центрами окружностей x²+y²-10x+16y+80=0 и
x²+y²+6x+4y-12=0
2) Найти угол наклона к оси OX прямой
А(-3;-3) В(-4;-4)
3) Решите уравнение x/A³ₓ=1/12
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sedinalana
Verified answer
1
(x²-10x+25)-25+(y²+16y+64)-64+80=0
(x-5)²+(y+8)²=9
O1(5;-8),R1=3
(x²+6x+9)-9+(y²+4y+4)-4-12=0
(x+3)²+(y+2)²=25
O2(-3;-2),R2=5
|O1O2|=√(-3-5)²+(-2+8)²=√(64+36)=√100=10
2
y=kx+b
-3=-3k+b
-4=-4k+b
отнимем
1=k
-3=-3+b
b=0
y=x
tga=1
a=45гр
3
x/(x(x-1)(x-2))=1/12
(x-1)(x-2)=12
x²-x-2x+2-12=0
x²-3x-10=0
x1+x2=3 U x1*x2=-10
x1=-2 не удов усл
x2=5
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Answers & Comments
Verified answer
1(x²-10x+25)-25+(y²+16y+64)-64+80=0
(x-5)²+(y+8)²=9
O1(5;-8),R1=3
(x²+6x+9)-9+(y²+4y+4)-4-12=0
(x+3)²+(y+2)²=25
O2(-3;-2),R2=5
|O1O2|=√(-3-5)²+(-2+8)²=√(64+36)=√100=10
2
y=kx+b
-3=-3k+b
-4=-4k+b
отнимем
1=k
-3=-3+b
b=0
y=x
tga=1
a=45гр
3
x/(x(x-1)(x-2))=1/12
(x-1)(x-2)=12
x²-x-2x+2-12=0
x²-3x-10=0
x1+x2=3 U x1*x2=-10
x1=-2 не удов усл
x2=5